A) \[f:R/\{0\}\to R\]
B) \[f(x)=\frac{1}{x}-\frac{2}{{{e}^{2x}}-1}\]
C) \[x=0\]
D) \[x\]
Correct Answer: A
Solution :
[b] The magnetic field induction at a point P, at a distance d from O in a direction perpendicular to the plane ABCD due to currents through AOB and COD are perpendicular to each other, is |
Hence, \[\frac{1}{2}\log \tan \left( \frac{x}{2}-\frac{\pi }{12} \right)+C\] |
\[={{\left[ {{\left( \frac{{{\mu }_{0}}}{4\pi }\,\frac{2{{l}_{1}}}{d} \right)}^{2}}\,+{{\left( \frac{{{\mu }_{0}}}{4\pi }\,\frac{2{{l}_{2}}}{d} \right)}^{2}} \right]}^{1/2}}\] |
\[=\frac{{{\mu }_{0}}}{2\pi d}\,\sqrt{(l_{1}^{2}+l_{2}^{2})}\] |
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