A) \[\frac{1}{3}m\]
B) \[\frac{1}{2}m\]
C) \[\frac{1}{6}m\]
D) \[\frac{2}{3}m\]
Correct Answer: C
Solution :
[c] |
\[mg\sin \theta ={{\mu }_{s}}mg\cos \theta \] |
[when partied is just balanced] |
\[\Rightarrow \]\[\tan \theta ={{\mu }_{s}}\] |
\[\tan \theta =\frac{dy}{dx}=\left( \frac{{{x}^{2}}}{2} \right)\] |
\[\therefore \]\[\frac{{{x}^{2}}}{2}=0.5\Rightarrow x=1\]\[\Rightarrow \]\[y=\frac{1}{6}\] |
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