A) 30 N
B) 25 N
C) 27 N
D) 48 N
Correct Answer: C
Solution :
[c] Minimum force on A= frictional force between the surfaces= 12 N |
Therefore maximum acceleration |
\[{{a}_{\max }}=\frac{12N}{4kg}=3m\text{/}{{s}^{2}}\] |
Hence maximum force, |
\[{{F}_{\max }}=\]total mass \[\times {{a}_{\max }}\] |
\[=9\times 3=27N\] |
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