The current i in the network is [JEE MAIN Held on 09-01-2020 Evening] |
A) 0.3A
B) 0.6 A
C) 0 A
D) 0.2 A
Correct Answer: A
Solution :
[a] Both the diodes are reverse biased \[I=\frac{9}{30}=0.3A\]You need to login to perform this action.
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