A particle is released on a vertical smooth semicircular track from point X so that OX makes angle q from the vertical (see figure). The normal reaction of the track on the particle vanishes at point Y where OY makes angle \[\phi \] with the horizontal. Then: [JEE ONLINE 19-04-2014] |
A) \[\sin \phi =\cos \phi \]
B) \[\sin \phi =\frac{1}{2}\cos \theta \]
C) \[\sin \phi =\frac{2}{3}\cos \theta \]
D) \[\sin \phi =\frac{3}{4}\cos \theta \]
Correct Answer: C
You need to login to perform this action.
You will be redirected in
3 sec