A) 56 %
B) 62 %
C) 44 %
D) 50 %
Correct Answer: A
Solution :
[a]along x-axis |
\[2m(2v)=3.{{v}_{x}}\Rightarrow {{v}_{x}}=\frac{2v}{3}\] |
\[2m(v)=3m{{v}_{y}}\Rightarrow {{v}_{y}}=\frac{2v}{3}\] |
\[{{v}_{net}}=\sqrt{v_{x}^{v}+u_{y}^{v}}=\frac{2\sqrt{2}v}{3}\] |
1144 |
\[=\frac{1}{2}m{{(2v)}^{2}}+\frac{1}{2}\left( 2m \right){{v}^{2}}-\frac{1}{2}\left( 3m \right){{\left( \frac{2\sqrt{2}}{3} \right)}^{2}}\]AO IIT ACADEMY / JEE - MAIN EXAM - 2015 / QP + Solutions / \[=3m{{v}^{2}}-\frac{4m{{v}^{2}}}{3}=\frac{5m{{v}^{2}}}{2}\] |
\[=\frac{loss\,in\,K.E}{Initial\,K.E}\times 100\] |
\[=\frac{5/3m{{v}^{2}}}{3m{{v}^{2}}}\times 100=5/9\times 100=56%\]D |
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