A) 32
B) 16
C) 8
D) none of these
Correct Answer: A
Solution :
According to Grahams law \[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] \[\therefore \] \[\frac{{{r}_{X}}}{{{r}_{Y}}}=\sqrt{\frac{{{M}_{Y}}}{{{M}_{X}}}}\] or \[\frac{2{{r}_{Y}}}{{{r}_{Y}}}=\sqrt{\frac{{{M}_{Y}}}{8}}\] \[(\because {{r}_{X}}=2{{r}_{Y}})\] \[\therefore \] \[4=\frac{{{M}_{Y}}}{8}\] or \[{{M}_{Y}}=32\]
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