A) \[9\times {{10}^{20}}ergs\]
B) \[7\times {{10}^{15}}ergs\]
C) \[5\times {{10}^{10}}ergs\]
D) \[3\times {{10}^{5}}\,ergs\]
Correct Answer: A
Solution :
According to \[E=m{{c}^{2}}\] \[m=1\,g,\] \[c=3\times {{10}^{10}}\,cm\,\,{{\sec }^{-1}}\] \[\therefore \] \[E=1\,g\times {{(3\times {{10}^{10}}\,cm\,\,{{\sec }^{-1}})}^{2}}\] \[=9\times {{10}^{20}}ergs\]You need to login to perform this action.
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