A) 2
B) 8
C) 64
D) 128
Correct Answer: C
Solution :
Actual vapour density of methane \[=\frac{mol\,.\,wt}{2}=\frac{16}{2}=8\] \[\therefore \] vapour density of volatile substance \[=8\times 4=32\] Molecular weight of the substance \[=32\times 2=64\]You need to login to perform this action.
You will be redirected in
3 sec