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JIPMER Jipmer Medical Solved Paper-2006

  • question_answer
    There are 26 tuning forks arranged in the decreasing order of their frequencies. Each tuning fork gives 3 beats with the next. The first one is octave of the last. What is the frequency of 18th tuning fork?

    A) 100 Hz       

    B)                        99 Hz                    

    C) 96 Hz                    

    D)        103 Hz

    Correct Answer: B

    Solution :

    Each tuning forck gives 3 beats with the next, so the difference in the frequencies of two consecutive forks is 3. \[\therefore \]  \[{{f}_{26}}={{f}_{1}}+(n-1)\times -\,3\] \[f=2f+(26-1)\times -3\] \[f=75\,Hz.\] \[\therefore \] Frequency of 18th tuning fork \[{{f}_{18}}={{f}_{1}}+(18-1)\times -\,3\]       \[=2\times 75+17\times -\,3\]       \[=150-51-99\,Hz\].


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