A) 0.549
B) 0.200
C) 0.786
D) 0.478
Correct Answer: D
Solution :
Total vapour pressure of mixture = (Mole fraction of pentane\[\times \]VP of pentane) + (Mole fraction of hexane\[\times \]VP of hexane) = VP of pentane in mixture +VP of hexane in mixture \[=\left( \frac{1}{5}\times 440+\frac{4}{5}\times 120 \right)=184\,mm\] \[\because \] VP of pentane in mixture = VP of mixture x mole fraction of pentane in vapour phase \[88=184\,\times \] mole fraction of pentane in vapour phase \[\therefore \] Mole fraction of pentane in vapour phase \[=\frac{88}{184}=0.478\]You need to login to perform this action.
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