A) 22.4 L
B) 44.8 L
C) 5.6 L
D) 11.2 L
Correct Answer: C
Solution :
From second law of Faraday \[\frac{{{m}_{Al}}}{{{m}_{H}}}=\frac{{{E}_{Al}}}{{{E}_{H}}}\] \[\therefore \] \[\frac{4.5}{{{m}_{H}}}=\frac{27/3}{1}\] or \[{{m}_{H}}=0.5\,g\] \[\because \] \[2g\,{{H}_{2}}\] volume at STP = 22.4 L \[\therefore \]\[0.5g\,{{H}_{2}}\] volume at STP \[=\frac{22.4\times 0.5}{2}L=5.6\,L\]You need to login to perform this action.
You will be redirected in
3 sec