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JIPMER Jipmer Medical Solved Paper-2009

  • question_answer
    9.2 g \[{{N}_{2}}{{O}_{4}}\] is heated in a 1 L vessel till equilibrium state is established \[{{N}_{2}}{{O}_{4}}(g)2N{{O}_{2}}(g)\] In equilibrium state 50%\[{{N}_{2}}{{O}_{4}}\]was dissociated, equilibrium constant will be (mol. wt. of \[{{N}_{2}}{{O}_{4}}=92\])

    A)  0.1                                        

    B)  0.4                        

    C)  0.3                        

    D)         0.2

    Correct Answer: D

    Solution :

    \[{{N}_{2}}{{O}_{4}}(g)2N{{O}_{2}}(g)\] Molar concentration of \[[{{N}_{2}}{{O}_{4}}]=\frac{9.2}{92}=0.1\,mol\text{/}L\] In equilibrium state when it 50% dissociates, \[[{{N}_{2}}{{O}_{4}}]=0.05\,M\] \[[N{{O}_{2}}]=0.1\,M\] \[{{K}_{c}}=\frac{{{[N{{O}_{2}}]}^{2}}}{[{{N}_{2}}{{O}_{4}}]}\]       \[=\frac{0.1\times 0.1}{0.05}=0.2\]


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