question_answer

The work done in increasing the size of a soap film for\[10\,cm\times 6\,m\]to \[10\,cm\times 11\,cm\]is\[3\times {{10}^{-4}}J.\] The surface tension of the film is

A)  \[1.0\times {{10}^{-2}}\text{ }N\text{/}m\]  

B)  \[6.0\times {{10}^{-2}}\text{ }N\text{/}m\]

C)  \[3.0\times {{10}^{-2}}\,N\text{/}m\]   

D)         \[1.5\times {{10}^{-2}}\text{ }N\text{/}m\]