A) 1
B) 2.5
C) 4
D) 5
Correct Answer: D
Solution :
\[[{{H}_{3}}{{O}^{+}}]=\sqrt{{{K}_{a}}\times C}\] \[=\sqrt{4\times {{10}^{-10}}\times 2.5\times {{10}^{-1}}}\] \[=\sqrt{{{10}^{-10}}}={{10}^{-5}}M\] \[\because \] \[pH=-\log [{{H}_{3}}{{O}^{+}}]\] \[\therefore \] \[pH=-\log ({{10}^{-5}})=5\]You need to login to perform this action.
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