A) \[40\,\,J/g\]
B) \[117\,\,J/g\]
C) \[167.7\,\,J/g\]
D) \[420.05\,\,J/g\]
Correct Answer: C
Solution :
\[\Delta G-ns\Delta T=(125+10.5)\times 1\times 3.1\] \[=420.05cal=\frac{420.05}{10.5}cal/g\] \[=40cal/g=167.7\,\,J/g\]You need to login to perform this action.
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