A) \[1.6\,\,g\]
B) \[2.2\,\,g\]
C) \[4.0\,\,g\]
D) \[1.6\,\,g\]
Correct Answer: A
Solution :
\[E-40GWh=40\times {{10}^{9}}J/s\] \[(60\times 60)=1.44\times {{10}^{14}}J\] \[E=m{{c}^{2}}\] \[m=\frac{E}{{{C}^{2}}}=\frac{1.44\times {{10}^{14}}}{{{(3\times {{10}^{8}})}^{2}}}=1\times {{10}^{3}}kg\] \[m=1.6\,\,g\]You need to login to perform this action.
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