A) \[6/5\]
B) \[5/6\]
C) \[1\]
D) \[4/5\]
Correct Answer: A
Solution :
\[y=k\,\,{{t}^{2}}\] \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=2k\] \[a=2m/{{s}^{2}}\] \[{{T}_{1}}=2\pi \sqrt{\frac{l}{g}}\] \[{{T}_{2}}=2\pi \sqrt{\frac{l}{g+{{a}_{y}}}}\] \[\frac{T_{1}^{2}}{T_{2}^{2}}=\frac{g+{{a}_{y}}}{g}\] \[=\frac{10+2}{10}=\frac{6}{5}\]You need to login to perform this action.
You will be redirected in
3 sec