A) 8.4
B) 6.2
C) 3.8
D) 5.6
Correct Answer: C
Solution :
\[HO{{\overset{+}{\mathop{NH}}\,}_{3}}+{{H}_{2}}OHON{{H}_{3}}OH+{{H}^{+}}\] \[{{K}_{h}}=\frac{{{K}_{w}}}{{{k}_{b}}}=\frac{{{10}^{-14}}}{{{10}^{-8}}}={{10}^{-6}}\] \[[{{H}^{+}}]=\sqrt{{{K}_{h}}C}\] \[=\sqrt{{{10}^{-6}}\times 0.024}\] \[=1.5\times {{10}^{-4}}\] and \[pH=3.8\]You need to login to perform this action.
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