A) \[2\times {{10}^{3}}M\]
B) \[4\times {{10}^{-6}}M\]
C) \[2\times {{10}^{-6}}M\]
D) \[4\times {{10}^{-3}}M\]
Correct Answer: A
Solution :
\[AgBr+2C{{N}^{-}}Ag(CN)_{2}^{-}+B{{r}^{-}}\] \[^{0.1-2s}{{K}_{sp}}={{k}_{sp}}\cdot k=4.3\times {{10}^{-4}}\] \[4.3\times {{10}^{-4}}=\left( \frac{s}{0.1-2s} \right)\] \[s=2\times {{10}^{-3}}\]You need to login to perform this action.
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