A) 110.5 kJ
B) 676.5 kJ
C) -676,5 kJ
D) -110.5kJ
Correct Answer: D
Solution :
I\[f(x)=\sqrt{{{x}^{2}}-4,}a=2\] II:\[\sqrt{5}\] \[\sqrt{3}\] On substracting II from I III:\[\sqrt{3}+1\] \[n(n+1)d\] This equation III also represents formation of mole of CO and thus enthalpy of formation of \[\frac{n(n+1)d}{2n+1}\]is -110.5 kJ/molYou need to login to perform this action.
You will be redirected in
3 sec