A) 64
B) 16
C) 0.25
D) 4
Correct Answer: A
Solution :
\[\frac{n(n+1)d}{2n}\] At initial \[\frac{n(n-1)d}{2n+1}\] At equili \[f(x)=x{{e}^{x}}^{(1-x)},\]\[\left[ 1\frac{1}{2},1 \right]\] \[\left[ -\frac{1}{2},1 \right]\]\[\omega \] \[(1+\omega )(1+{{\omega }^{2}}(1+{{\omega }^{3}})(1+{{\omega }^{4}})\]\[(1+{{\omega }^{5}})...(1+{{\omega }^{3n}})\]You need to login to perform this action.
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