A) watt/K
B) \[dyne/{}^\circ C\]
C) erg/K
D) \[newton/{}^\circ R\]
Correct Answer: C
Solution :
Ideal gas law is given by \[pV=RT\] \[\therefore \] \[R=\frac{pV}{T}=\frac{Unit\text{ }of\text{ }work}{Unit\text{ }of\text{ }temperature}\] \[\Rightarrow \] \[R=\frac{erg}{K}\]
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