A) 0.0001%
B) 0.01%
C) 0.1%
D) 0.15%
Correct Answer: B
Solution :
\[{{X}^{-}}+{{H}_{2}}OHX+O{{H}^{-}}\] \[{{K}_{h}}=\frac{{{10}^{-14}}}{{{10}^{-5}}}\] So, degree of hydrolysis \[x=\sqrt{\frac{{{K}_{h}}}{C}}=\sqrt{\frac{{{10}^{-9}}}{{{10}^{-1}}}}={{10}^{-4}}\] % degree of hydrolysis \[={{10}^{-4}}\times 100=0.01%\]You need to login to perform this action.
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