A) weaker electron-electron repulsion in \[Cl\]
B) higher atomic radius of F
C) smaller electronegativity of F
D) more vacant p-subshell in \[Cl\]
Correct Answer: A
Solution :
Electron affinity value of\[Cl\]is higher than that of F as\[Cl\]belongs to 3rd period while F belongs to 2nd period. In\[Cl,\]electron-electron repulsion forces are weaker than that of F.You need to login to perform this action.
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