A) \[C{{H}_{3}}CH(Br)C{{H}_{3}}\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]
C) \[C{{H}_{2}}=CHBr\]
D) \[BrCH=CHC{{H}_{3}}\]
Correct Answer: A
Solution :
\[\underset{Acetylene}{\mathop{CH\equiv CH}}\,\xrightarrow[{{H}_{2}}S{{O}_{4}}]{HgS{{O}_{4}}}\underset{Acetaldehyde}{\mathop{C{{H}_{3}}CHO}}\,\] \[\xrightarrow{C{{H}_{3}}MgBr}C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} OMgBr \\ | \end{smallmatrix}}{\mathop{C}}}\,-H\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} Br \\ | \end{smallmatrix}}{\mathop{C}}}\,-H\xleftarrow[{}]{P/B{{r}_{2}}}\underset{Isopropyl\,alcohol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}}\,-H}}\,\]You need to login to perform this action.
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