A) 891 Hz
B) 900 Hz
C) 1089 Hz
D) 1100 Hz
Correct Answer: C
Solution :
From Dopple?s effect the perceived frequency \[f'\]is given by \[f'=f\left( \frac{v+{{v}_{0}}}{v} \right)\] Given\[f=990\text{ }Hz,\text{ }v=300\text{ }m/s,\text{ }{{v}_{0}}=33\text{ }m/s\] \[\therefore \] \[f'=990\left( \frac{330+33}{330} \right)\] \[=990\times \frac{363}{330}=1089\,Hz\]You need to login to perform this action.
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