A) 9.0cm
B) 7.5cm
C) 6.0cm
D) 3.0cm
Correct Answer: D
Solution :
Height to which water rises in the capillary tube is \[h=\frac{2T\,\cos \theta }{r\rho g}\] Given, \[T=75\text{ }dyne/cm,\text{ }\theta =0{}^\circ ,\text{ }r=\frac{1}{2}\times 10\text{ }cm,\] \[g=10\text{ }m/{{s}^{2}},\rho =1\text{ }g/cc\] \[\therefore \] \[h=\frac{2\times 75\times \cos {{0}^{o}}\times 2}{10\times 10}=3cm\]You need to login to perform this action.
You will be redirected in
3 sec