A) 20V/m
B) 6V/m
C) 11 V/m
D) -23V/m
Correct Answer: A
Solution :
Voltage\[V=5{{x}^{2}}+10x-9\] Electric field\[E=-\frac{dV}{dx}=-\frac{d}{dx}(5{{x}^{2}}+10x-9)\] \[=-(10x-10)\] At \[x=1\text{ }m\] \[\therefore \] \[E=10(1)+10=20\,V/m\]You need to login to perform this action.
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