A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
For coincidence of bonds \[\frac{nD{{\lambda }_{1}}}{d}=\frac{(n+1)D{{\lambda }_{L}}}{d}\] \[n{{\lambda }_{1}}=(n+1){{\lambda }_{L}}\] \[7800n=5200(n+1)\Rightarrow n=2\]You need to login to perform this action.
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