A) \[\frac{12}{25}s\]
B) \[\frac{24}{25}s\]
C) \[\frac{35}{24}s\]
D) \[\frac{15}{12}s\]
Correct Answer: A
Solution :
Under the influence of one force\[{{F}_{1}}=m\omega _{1}^{2}y\] and under the action of another force. \[{{F}_{2}}=m\omega _{2}^{2}y\] \[F={{F}_{1}}+{{F}_{2}}\] \[m{{\omega }^{2}}y=m\omega _{1}^{2}y+m\omega _{2}^{2}y\] \[{{\omega }^{2}}=\omega _{1}^{2}+\omega _{2}^{2}\] \[{{\left[ \frac{2\pi }{T} \right]}^{2}}={{\left[ \frac{2\pi }{{{T}_{1}}} \right]}^{2}}+{{\left( \frac{2\pi }{{{T}_{2}}} \right)}^{2}}\] \[T=\sqrt{\frac{T_{1}^{2}\times T_{2}^{2}}{T_{1}^{2}+T_{2}^{2}}}\] \[=\sqrt{\frac{{{\left( \frac{4}{5} \right)}^{2}}{{\left( \frac{3}{5} \right)}^{2}}}{{{\left( \frac{4}{5} \right)}^{2}}+{{\left( \frac{3}{5} \right)}^{2}}}}=\frac{12}{25}s\]You need to login to perform this action.
You will be redirected in
3 sec