A) \[\frac{{{A}_{1}}}{{{A}_{2}}}\]
B) \[1:1\]
C) \[\frac{{{A}_{2}}}{{{A}_{1}}}\]
D) data insufficient
Correct Answer: C
Solution :
Since, resolving power of telescope \[(R)=\frac{1}{d\theta }=\frac{A}{1.22\lambda },\]where A is the aperture or diameter of objective lens. From this formula \[R\propto A\] Therefore, \[\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{{{A}_{2}}}{{{A}_{1}}}\]You need to login to perform this action.
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