A) 48 cm
B) 45 cm
C) 80 cm
D) 90 cm
Correct Answer: A
Solution :
Here, \[u=+12cm,f=-16\,cm=v=?\] By lens equation \[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\] Substituting the values \[\frac{1}{-16}=\frac{1}{v}-\frac{1}{12}\] \[\frac{1}{v}=\frac{1}{12}-\frac{1}{16}=\frac{4-3}{48}=\frac{1}{48}\] \[v=+48\,cm\] The image of virtual object P forms at P at a distance of 48 cm from lens.You need to login to perform this action.
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