A) \[O_{2}^{-},O_{2}^{2-}-\]Both diamagnetic
B) \[{{O}^{+}},\,O_{2}^{2-}-\]Both paramagnetic
C) \[O_{2}^{+},\,{{O}_{2}}-\] Both paramagnetic
D) \[O_{{}}^{{}},O_{2}^{2-}-\]Both paramagnetic
Correct Answer: C
Solution :
The molecular orbital configurations of |
\[O_{2}^{+},O_{2}^{-},O_{2}^{2-}\]and\[{{O}_{2}}\] are |
\[O_{2}^{+}=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\overset{{}}{\mathop{\sigma }}\,2s_{z}^{2},\pi 2p_{x}^{2}\approx \pi 2p_{y}^{2},\]\[\overset{*}{\mathop{\pi }}\,2p_{x}^{1}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{2}\] |
\[O_{2}^{-}=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2},\pi 2p_{x}^{2}\] |
\[\approx \pi 2p_{y,}^{2}\overset{*}{\mathop{\pi }}\,2p_{x}^{2}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{1}\] |
\[O_{2}^{2}-=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2s_{z}^{2},\pi 2p_{x}^{2}\] |
\[\approx \pi 2p_{y,}^{2}\overset{*}{\mathop{\pi }}\,2p_{x}^{2}\approx \overset{*}{\mathop{\pi }}\,2p_{y.}^{2}\] |
\[{{O}_{2}}=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\sigma 2p_{z}^{2},\pi 2p_{x}^{2}\] |
\[\approx \pi 2p_{y,}^{2}\overset{*}{\mathop{\pi }}\,2p_{x}^{1}\approx \overset{*}{\mathop{\pi }}\,2p_{y}^{1}\] |
And the electronic configuration of O and \[{{O}^{+}}\]are |
\[O=1{{s}^{2}},2{{s}^{2}},2p_{x,}^{2}2p_{y,}^{1}2p_{z}^{1}\] |
\[{{O}^{+}}=1{{s}^{2}},\,2{{s}^{2}},\,2p_{x}^{1},\,2p_{y}^{1},\,2p_{z}^{1}\] |
As\[O_{2}^{+},{{O}_{2}},O_{2,}^{-}O\]and \[{{O}^{+}}\]have unpaired electrons, hence are paramagnetic. |
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