A) 60 s
B) 80 s
C) 20 s
D) 40 s
Correct Answer: D
Solution :
For 40 g amount |
\[40\,g\xrightarrow[\text{half-life}]{20\,s}20\,g\xrightarrow[{}]{20\,s}10g\] |
For 160 g amount |
\[160\,g\xrightarrow{10\,s}80\,g\xrightarrow[{}]{10\,s}40g\] |
\[\xrightarrow[{}]{10\,s}20\,g\xrightarrow[{}]{10\,s}10g\] |
So, after \[40s\,{{A}_{1}}\] and \[{{A}_{2}}\] remains same. |
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