A) 1
B) 2
C) 4
D) 9
Correct Answer: B
Solution :
Key Idea: In case of bcc lattice, there are eight atoms at the eight corners of the unit cell and one atom at the body centre. |
Number of atoms per unit cell is given by |
\[N={{N}_{b}}+\frac{{{N}_{f}}}{2}\times \frac{{{N}_{c}}}{8}\] |
where \[{{N}_{b}}=\] number of atoms centred in this body |
\[{{N}_{f}}=\] number of atoms centred in the face |
\[{{N}_{c}}=\] number of atoms centred at the corner |
For bcc structure, \[{{N}_{b}}=1,\text{ }{{N}_{f}}=0\] and \[{{N}_{c}}=8\] |
\[\therefore \] \[N=1+\frac{0}{2}+\frac{8}{8}=2\] |
You need to login to perform this action.
You will be redirected in
3 sec