A) 6
B) 12
C) 24
D) 48
Correct Answer: C
Solution :
Given \[\frac{{{I}_{C}}}{{{I}_{E}}}=\] current gain \[(\alpha )=0.96\] |
So, current gain in common emitter configuration is |
\[\beta =\frac{\alpha }{1-\alpha }\] |
\[=\frac{0.96}{1-0.96}-\frac{0.96}{0.04}\] |
= 24 |
Note: The current gain \[\beta \] in common emitter mode is very large as compared to the current gain \[\alpha \] in common base mode. This is why a transistor is always used as an amplifier in the CE mode. |
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