| The input signal given to a CE amplifier having a voltage gain of 150 is |
| \[{{V}_{i}}=2\cos \left( 15t+\frac{\pi }{3} \right)\] The corresponding output signal will be [NEET (Re) 2015] |
A) \[300\cos \left( 15t+\frac{\pi }{3} \right)\]
B) \[75\cos \left( 15t+\frac{2\pi }{3} \right)\]
C) \[2\cos \left( 15t+\frac{5\pi }{3} \right)\]
D) \[300\cos \left( 15t+\frac{4\pi }{3} \right)\]
Correct Answer: D
Solution :
| Input signal of a CE amplifer, \[{{V}_{in}}=2\cos \left( 15t+\frac{\pi }{3} \right)\] |
| Voltage gain \[{{A}_{v}}=150\] |
| As CE amplifier gives phase difference of n between input and output signals. |
| So \[{{A}_{v}}=\frac{{{V}_{0}}}{{{V}_{in}}}\Rightarrow {{V}_{0}}={{A}_{v}}{{V}_{in}}\] |
| \[{{V}_{0}}=150\times 2\cos \left( 15t+\frac{\pi }{3}+\pi \right)\] |
| \[V=300\cos \left( 15t+\frac{4\pi }{3} \right)\] |
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