| Consider the junction diode as ideal. The value of current flowing through AB is : [NEET - 2016] |
 |
A) \[0\,A\]
B) \[{{10}^{-2}}A\]
C) \[{{10}^{-1}}A\]
D) \[{{10}^{-3}}A\]
Correct Answer: B
Solution :
| [b] Since diode is in forward bias |
| \[i=\frac{\Delta V}{R}=\frac{4-(-6)}{1\times {{10}^{3}}}=\frac{10}{{{10}^{3}}}={{10}^{-2}}A\] |
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