A) \[C{{O}_{2}},\text{ }N{{O}_{2}}\]
B) \[NO_{2}^{-},\,C{{O}_{2}}\]
C) \[C{{N}^{-}},\text{ }CO\]
D) \[S{{O}_{2}},\,C{{O}_{2}}\]
Correct Answer: C
Solution :
\[C{{N}^{-}}\] and CO are iso-electronic because they have equal number of electrons. |
In \[C{{N}^{-}}\] the no. of electrons \[=~6+7+1=14\] |
In CO the no. of electrons \[=\text{ }6+8=14\] |
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