A) \[4\times {{10}^{1}}\]
B) \[3\times {{10}^{7}}\]
C) \[2\times {{10}^{-25}}\]
D) \[5\times {{10}^{-18}}\]
Correct Answer: A
Solution :
\[\therefore \] Frequency \[=\frac{c}{\lambda }=\frac{3\times {{10}^{8}}m\,{{s}^{-1}}}{8\times {{10}^{15}}\,{{s}^{-1}}}\] |
\[=0.375\times {{10}^{-7}}\,m\] |
\[=3.75\times {{10}^{1}}\,nm\,\approx \,4\times {{10}^{1}}\,nm\] |
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