A) K
B) K/4
C) K/2
D) zero
Correct Answer: C
Solution :
For net intensity |
\[l'=4{{l}_{0}}{{\cos }^{2}}\frac{\phi }{2}\left( \phi =\frac{2\pi }{\lambda }\times \lambda \right)\] |
For the first case, |
\[K=4{{l}_{0}}{{\cos }^{2}}[\pi ]\] |
\[K=4{{l}_{0}}\] (i) |
For the second case |
\[K'=4{{l}_{0}}{{\cos }^{2}}\left( \frac{\pi /2}{2} \right)\left( \phi =\frac{2\pi }{\lambda }\times \frac{\lambda }{4} \right)\] |
\[4{{l}_{0}}{{\cos }^{2}}(\pi /2)\] |
\[K'=2{{l}_{0}}\] (ii) |
Comparing Eqs. (i) and (ii) |
\[K'=K/2\] |
You need to login to perform this action.
You will be redirected in
3 sec