A) \[\frac{2\lambda D}{a}\]
B) \[\frac{D\lambda }{a}\]
C) \[\frac{Da}{\lambda }\]
D) \[\frac{2Da}{\lambda }\]
Correct Answer: A
Solution :
For the condition of maxima |
\[\sin \theta =\frac{\lambda }{a}\] |
From the geometry, |
\[\sin \theta =\theta =\frac{Y}{D}\] (for small angle) |
So, \[\frac{Y}{D}=\frac{\lambda }{a}\] |
\[\Rightarrow \] \[\,Y=\frac{\lambda D}{a}\] |
Hence, width of central maxima \[=2Y=\frac{2\lambda D}{a}\] |
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