A) \[mg(h+d)+\frac{1}{2}k{{d}^{2}}\]
B) \[mg(h+d)-\frac{1}{2}k{{d}^{2}}\]
C) \[mg(h-d)-\frac{1}{2}k{{d}^{2}}\]
D) \[mg(h-d)+\frac{1}{2}k{{d}^{2}}\]
Correct Answer: B
Solution :
Key Idea: Work done is equal to change in energy of body. |
Situation is shown in figure. When mass m falls vertically on spring, then spring is compressed by distance d. |
Hence, net work done in the process is |
\[W=\] Potential energy stored in the spring + Loss of potential energy of mass\[=mg\,(h+d)-\frac{1}{2}\,k{{d}^{2}}\] |
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