A) \[\mu =\frac{1}{\tan \theta }\]
B) \[\mu =\frac{2}{\tan \theta }\]
C) \[\mu =2\tan \theta \]
D) \[\mu =\tan \theta \]
Correct Answer: C
Solution :
The block may be stationary, when \[mg\sin \theta \cdot L=\alpha mg\cos \theta \frac{L}{2}\] or \[\alpha =\frac{mg\sin \theta \cdot L}{mg\cos \theta \frac{L}{2}}\] \[=2\frac{\sin \theta }{\cos \theta }=2\tan \theta \] \[\alpha =2\tan \theta \]You need to login to perform this action.
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