A) 9 J
B) 6 J
C) 13 J
D) 15 J
Correct Answer: A
Solution :
Given, force F = 3 i + j \[{{r}_{1}}=(2i+k)m\]and\[{{r}_{2}}=(4i+3J-k)m\] \[\therefore \]\[s={{r}_{2}}-{{r}_{1}}=(4i+3j-k)-(2i+k)\] \[=(2i+3j-2k)m\] \[\therefore \]\[W=F\cdot s=(3i+j)\cdot (2i+3j-2k)\] \[\begin{align} & =3\times 2+3+0 \\ & =6+3=9\,J \\ \end{align}\]You need to login to perform this action.
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