A) nB
B) \[{{n}^{2}}B\]
C) 2nB
D) \[2{{n}^{2}}B\]
Correct Answer: B
Solution :
B= \[\frac{{{\mu }_{o}}I}{2r}\] when made an turn radius becomes r` \[n\times 2\pi r\grave{\ }=2\pi r\Rightarrow r\grave{\ }=\frac{r}{n}\] Now, B`=\[\frac{{{\mu }_{{}^\circ }}nI}{2r\grave{\ }}={{n}^{2}}\frac{{{\mu }_{{}^\circ }}I}{2r}={{n}^{2}}B\]You need to login to perform this action.
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