A) \[\frac{W}{\sqrt{3}}\]
B) \[\sqrt{3W}\]
C) \[\frac{\sqrt{3}W}{2}\]
D) \[\frac{2W}{\sqrt{3}}\]
Correct Answer: B
Solution :
\[W=PE(\cos {{\theta }_{1}}-\cos {{\theta }_{2}})\] \[W=PE(\cos 0-\cos {{60}^{{}^\circ }})\] =\[\frac{PE}{2}\] \[\Rightarrow PE=2W\] \[\tau =PE\,\sin \theta =2W\sin {{60}^{{}^\circ }}=\sqrt{3}W\]You need to login to perform this action.
You will be redirected in
3 sec