A) 1 GHz
B) 100 MHz
C) 62.8 MHz
D) 6.28 MHz
Correct Answer: A
Solution :
\[f=\frac{qB}{2\pi m}=\frac{1.67\times {{10}^{11}}\times 3.57\times {{10}^{-2}}}{2\times 3.14}\] \[{{10}^{9}}HZ=1GHz\]You need to login to perform this action.
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