A) \[{{10}^{o}}\]
B) \[{{4}^{o}}\]
C) \[{{6}^{o}}\]
D) \[{{8}^{o}}\]
Correct Answer: C
Solution :
\[(\mu -1)+(\mu '-1)A'=0\] \[\left| (\mu -1)A \right|=\left| (\mu '-1)A' \right|\] \[(1.42-1)\times {{10}^{o}}=(1.7-1)A'\] \[4.2=0.7\,A'\] \[A'={{6}^{o}}\]You need to login to perform this action.
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